'''Pollard's rho algorithm for logarithms''' is an algorithm for solving the [[discrete logarithm]] problem analogous to [[Pollard's rho algorithm]] for solving the [[Integer factorization]] problem.
The algorithm computes such that , where belongs to the [[group]] generated by . The algorithm computes integers , , , and such that . Assuming, for simplicity, that the underlying group is cyclic of order , we can calculate as a solution of the equation .
To find the needed , , , and the algorithm uses [[Floyd's cycle-finding algorithm]] to find a cycle in the sequence , where the function is assumed to be random-looking and thus is likely to enter into a loop after approximately steps. One way to define such a function is to use the following rules: Divide into three subsets (not necessarily [[subgroup]]s) of approximately equal size: , , and . If is in then double both and ; if then increment , if then increment .
==Algorithm==
Let be a cyclic group of prime order , and given , and a partition , let be a map
and define maps and by
:'''Inputs''' ''a'' a generator of ''G'', ''b'' an element of ''G''
:'''Output''' An integer ''x'' such that ''ax = b'', or failure
:# Initialise ''a0'' ← 0
:#::''b0'' ← 0
:#::''x0'' ← 1 ∈ ''G''
:#::''i'' ← 1
:# ''xi'' ← ''f(xi-1)'', ''ai'' ← ''g(xi-1,ai-1)'', ''bi'' ← ''h(xi-1,bi-1)''
:#''x2i'' ← ''f(f(x2i-2))'', ''a2i'' ← ''g(f(x2i-2),g(x2i-2,a2i-2))'', ''b2i'' ← ''h(f(x2i-2),h(x2i-2,b2i-2))''
:# If ''xi'' = ''x2i'' then
:## ''r'' ← ''bi'' - ''b2i''
:## If r = 0 return failure
:## x ← ''r-1''(''a2i'' - ''ai'') mod ''p''
:## return x
:# If ''xi'' ≠ ''x2i'' then ''i'' ← ''i+1'', and go to step 2.
==Example==
Consider, for example, the group generated by 2 modulo (the order of the group is , 2
generates the group of units modulo 1019). The algorithm is implemented by the following [[C++]] program:
#include
const int n = 1018, N = n + 1; // N = 1019 -- prime
const int alpha = 2; // generator
const int beta = 5; // 2^{10} = 1024 = 5 (N)
void new_xab(int& x, int& a, int& b){
switch(x%3){
case 0: x = x*x % N; a = a*2 % n; b = b*2 % n; break;
case 1: x = x*alpha % N; a = (a+1) % n; break;
case 2: x = x*beta % N; b = (b+1) % n; break;
}
}
int main(){
int x=1, a=0, b=0;
int X=x, A=a, B=b;
for(int i = 1; i < n; ++i){
new_xab(x, a, b);
new_xab(X, A, B); new_xab(X, A, B);
printf("%3d %4d %3d %3d %4d %3d %3d\n", i, x, a, b, X, A, B);
if(x == X) break;
}
return 0;
}
The results are as follows (edited):
i x a b X A B
------------------------------
1 2 1 0 10 1 1
2 10 1 1 100 2 2
3 20 2 1 1000 3 3
4 100 2 2 425 8 6
5 200 3 2 436 16 14
6 1000 3 3 284 17 15
7 981 4 3 986 17 17
8 425 8 6 194 17 19
..............................
48 224 680 376 86 299 412
49 101 680 377 860 300 413
50 505 680 378 101 300 415
51 1010 681 378 1010 301 416
That is and so , for which is a solution as expected. As is not prime, there is another solution , for which holds.
==References==
* J. Pollard, ''Monte Carlo methods for index computation mod p'', Mathematics of Computation, Volume 32, 1978.
* Alfred J. Menezes, Paul C. van Oorschot, and Scott A. Vanstone, [http://www.cacr.math.uwaterloo.ca/hac/about/chap3.pdf Handbook of Applied Cryptography, Chapter 3], 2001.
[[category:logarithms]]